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In right triangle ABC, sin B = 2x+0.42 B=2x+0.42 and cos C = 9x+0.84 C=9x+0.84. Solve for xx.

In right triangle ABC, sin B = 2x+0.42 B=2x+0.42 and cos C = 9x+0.84 C=9x+0.84. Solve for xx.
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In right triangle ABC, sin B = 2x+0.42 B=2x+0.42 and cos C = 9x+0.84 C=9x+0.84. Solve for xx.

asked
User Alturkovic
by
8.2k points

1 Answer

8 votes

Answer:

-0.06

Explanation:

answered
User Chelsea Shawra
by
7.9k points
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