Question

if the sides of a square are increasing at a rate of 3 in/sec, at what rate is the area increasing when the edges are 10 in?

Answer 1

Below

Explanation:

Square area = s^2

ds/dt = 3

Area = s^2 Find the derivative with respect to t of both sides

area/dt = 2s ds/dt

= 2 (10)(3) = 60 in^2 per sec