Question

State the vertex and the axis of symmetry
y = 3(x-5)^2

Answer 1

Vertex = (5,0)

Axis of symmetry = x = 5

Step-by-step explanation:

Y = 3(x-5)^2

Equal 3(x-5) to 0

y = 3 = 0

x-5 = 0

x = 5

Vertex = (5,0)

Formula for Axis of symmetry: x = -b/2a

Write 3(x-5)^2 in standard form

Y = 3x^2 - 30x + 75

x = -b/2a

x = -(-30)/2(3)

x = 30/6

x = 5