asked 98.0k views
2 votes
G(x) = 2x - 1

h(x) = 1-g(x)
the functions g and h are defunded above. What is the value of h(0)

asked
User Andriana
by
8.0k points

1 Answer

2 votes

Answer:

2

Step-by-step explanation:

Since h (x) = 1 − g (x), substituting 0 for x yields h (0) = 1 − g (0). Evaluating g (0) gives g (0) = 2(0) − 1 = −1. Therefore, h (0) = 1 − (−1) = 2.

answered
User Suleidy
by
8.4k points

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