Question

Write an equation of the line passing through the point (4, 2) that is perpendicular to the line 4x+3y=7.

Answer 1

OK so what do you need help with

Answer 2

y = 3/4x - 1

Explanation:

4x + 3y = 7

3y = -4x + 7

y = -4/3x + 7/3

The slope of the given line is -4/3 so the slope of a line perpendicular to it is 3/4 (negative reciprocal).

y = 3/4x + b

Substitute x = 4 and y = 2:

2 = 3/4(4) + b

2 = 3 + b

b = -1

Thus the final equation is y = 3/4x - 1