Question

What is the mass in grams of a single molecule of water, h2o?

Answer 1

2.99 x 10^-23 g

Step-by-step explanation:

One mole of H20 equals 2(1.01) + 16 = 18.02 g

One mole of H20 also equals 6.022 x 10^23 molecules (Avogadro's constant)

so 6.022 x 10^23 molecules equal 18.02 g

therefore one molecule = (18.02)/(6.022 x 10^23) = 2.99 x 10^-23 g