Answer:
-sinh(1)sec^2(x)
Explanation:
The notation that I suppose you're using is d/dx.
Starting with
y = sinh−1(tan(x))
Simplify the trigonometric ratio sinh, then simplify:
d/dx(sinh(-tan(x))
d/dx [-sinh(1)tan(x)]
=-sinh(1) * d/dx [tan(x)]
Therefore, you get:
-sinh(1)sec^2(x)