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Write the complex number 8/1+i in standard form?

asked
User Xenocyon
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2 Answers

4 votes

Answer: 4-4i

Explanation:


\displaystyle\\(8)/(1+i) =\\\\(8(1-i))/((1+i)(1-i))=\\\\(8(1-i))/(1^2-i^2) =\\\\(8(1-i))/(1-(√(-1))^2 )=\\\\(8(1-i))/(1-(-1))=\\\\(8(1-i))/(1+1) =\\\\(8(1-i))/(2) =\\\\4(1-i)=\\\\4-4i

answered
User Tylerargo
by
7.9k points
0 votes

Answer: 8 + i

Explanation:

The complex number 8/1+i can be written in standard form as 8 + i. In standard form, a complex number is written as a+bi, where a is the real part and bi is the imaginary part. In this case, the real part is 8 and the imaginary part is i. Therefore, the standard form of the complex number 8/1+i is 8 + i.

answered
User Yogesh
by
8.0k points

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