Question

Write the equation of the circle with a radius of 10 and a center at (3,-1)

Answer 1

`\textsf{b)} \quad (x-3)^2+(y+1)^2=100`

Explanation:

`\boxed{\begin{minipage}{5 cm}\underline{Equation of a circle}\\\\$(x-h)^2+(y-k)^2=r^2$\\\\where:\\ \phantom{ww}$\bullet$ $(h, k)$ is the center. \\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}`

Given:

• center = (3, -1)
• radius = 10

Substitute the given center and radius into the formula to create the equation of a circle with the given parameters:

`\implies (x-3)^2+(y-(-1))^2=10^2`

`\implies (x-3)^2+(y+1)^2=100`