Question

Question

the third term of GP is 4 the product of its first 5 term is
please solve it
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Answer 1

`\huge{ \bold{ \color{purple}{Solution }}}`

Let a be the first term and r be the common ratio

Now,

`\large{ \sf{T _3 = 4}}`

`\large{ \sf{ {ar}^(2) = 4}}`

`\large{ \sf{ \therefore \: product \: of \: first \: 5 \: term \: = a _1 * a_2 * a_3 * a_4 * \: a _5}}`

`\large{ \sf{ = a(ar)( {ar}^(2) )( {ar}^(3) )( {ar}^(4) ) = {a}^(5) r {}^(10) }}`

`\large{ \sf{ \red{(ar {}^(2) ) {}^(5) = {4}^(5) }}}`

`\rule{150pt}{5pt}`