Question

According to the following balanced reaction, how many moles of NO are formed from 2.50 moles of NO2 if there is plenty of water present? 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)

Answer 1

0.83 moles

Step-by-step explanation:

To find the number of moles of NO that are formed from 2.50 moles of NO2 in the presence of plenty of water, we can use the mole ratio from the balanced chemical equation. The mole ratio is the ratio of the number of moles of each reactant and product in the chemical reaction.

In the given reaction, the mole ratio of NO2 to NO is 3:1. This means that for every 3 moles of NO2, 1 mole of NO is formed. Therefore, if we have 2.50 moles of NO2, the number of moles of NO that are formed will be 1/3 of that amount, which is 2.50 moles / 3 = 0.83 moles.

Therefore, the number of moles of NO that are formed from 2.50 moles of NO2 in the presence of plenty of water is 0.83 moles.