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Sin15°+tan65°=cot25°+cos75°

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Sin15°+tan65°=cot25°+cos75°

asked Nov 25, 2023 235k views

24 votes

Sin15°+tan65°=cot25°+cos75°

Mathematics
college

by Debran

8.4k points

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1 Answer

10 votes

Explanation:

L.H.S =

sin15°+tan65°

sin(90°-75°)+tan(90°-25°)

cos75°+cot25°

or; cot25°+ cos75°. R.H.S

Seventoes answered Nov 29, 2023

8.1k points

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