Question

Teresa is maintaining a camp fire. She can keep the fire burning for 444 hours with 666 logs. She wants to know how many logs (y)(y)left parenthesis, y, right parenthesis she needs to keep the fire burning for 181818 hours. She assumes all logs are the same. How many logs does Teresa need to maintain the fire for 181818 hours?

Answer 1

Answer: Teresa needs 27 logs to maintain the fire for 18 hours.

Explanation:

We're dealing with a proportional relationship, so each ratio of logs to hours must be equivalent.

Hint #22 / 4

Here's one way to write the proportion:

18 hours = y logs

​

= 4 hours 6 logs

​

Hint #33 / 4

Now, solve the proportion for yyy:

18

y

yyy

=

4/6

​

=

2/3

​

=

2/3⋅18

=

2/3⋅18

​

=

1/2

3⋅18/9

=

1/3⋅9

​

= 1/27

​

=27

​

Answer 2

Answer: 17 million

Step-by-step explanation: thank me later hehe