Question

Please I need help on question 7​

Answer 1

x = 90

y = 30°

∠ABC = 75°

Explanation:

Finding the angles of isosceles triangle:

ΔDAB is an isosceles triangle.

⇒ ∠ADB ≅ ∠ABD = y

In ΔABD ,

120 + y + y = 180 {Angle sum property of triangle}

120 + 2y = 180

2y = 180 - 120

2y = 60

y = 60 ÷ 2

`\sf \boxed{y = 30^\circ}`

ΔDCB is an isosceles triangle.

∠CDB ≅ ∠CBD = 45

x + 45 + 45 = 180

x + 90 = 180

x = 180 - 90

`\sf \boxed{x = 90^\circ}`

∠ABC = ∠ABD + ∠DBC

= 30 + 45

= 75°