Question

Differentiate with chain rule

Answer 1

`f'(x)=6cos((3)/(4)x-(\pi )/(5))`

Explanation:

`f(x)=8sin((3)/(4) x-(\pi )/(5)) \\`

`f'(x)=8cos((3)/(4)x-(\pi )/(5))*(3)/(4) \\`

`f'(x)=6cos((3)/(4)x-(\pi )/(5))`