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Given f(x) = (4 - x)² + 6, what is the value of ƒ (1)?

Given f(x) = (4 - x)² + 6, what is the value of ƒ (1)?
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Given f(x) = (4 - x)² + 6, what is the value of ƒ (1)?

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User Chech
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1 Answer

0 votes

Answer:

15

Explanation:


f(x)=(4-x)^2+6\\f(1)=(4-1)^2+6\\f(1)=(3)^2+6\\f(1)=9+6\\f(1)=15

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User Plof
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