Question

Consider the following quadratic equation:

49x2=64
Using the standard form ax2+bx+c=0 of the given quadratic equation, factor the left hand side of the equation into two linear factors.

Answer 1

⇒ let us first write the given equation in the form

`ax^(2) +bx+c=0`

⇒
`49x^(2) -64=0`

⇒ Note in this case bx=0

Let us factorize the equation...49 is a square number and 64 is also a square number ..This equation is a difference of two squares which can be written as:

`(7x-8)(7x+8)=0`

⇒The answer is (7x-8)(7x+8)=0