Question

What is the molarity of a solution containing 1.4 mol of acetic acid (HC₂H3O₂) in 218 mL of solution?

i
MHC₂H3O2

Answer 1

the molarity=6.42M

Step-by-step explanation:

from concentration = number of moles/ volume

=1.4mol/(0.218L)

=6.42M