Question

Consider the line y= 5/2x+5

1. find the equation of the line that is perpendicular to this line and passes through the point (-5,6)

2. find the equation of the line that is parallel to this line and passes through the point (-5,6)

Answer 1

Explanation:

1

y-6 = -2/5(x-(-5)
y - 6 = -2/5(x+5)

y -6 = -2/5 x -2

y = -2/5 x -2 + 6

y = -2/5 x + 4

2

y-6 = 5/2 (x-(-5)

y-6 = 5/2 (x+5)

y - 6 = 5/2 x + 25/2

y = 5/2 x + 25/2 + 6

y = 5/2 x + (25+12)/2

y = 5/2 x + 37/2