Question

What is the heat change when 1.25 g of water vapor at 185.3C is cooled to 102.1C?The specific heat of steam is 2.02J/g C

Answer 1

Answer: -210.08 J

Step-by-step explanation:

Use the formula q = (m)(c)(ΔT)

q = (1.25)(2.02)(102.1-185.3)

q = -210.08 J

This is exothermic! Heat is lost.