Question

Determine the amount of charge that has been passed if a 12W lamp that has a resistance of 270Ω has been run for 2.5 seconds.

Answer 1

Step-by-step explanation:

Given:

P = 12 W

R = 270 Ω

t = 2.5 s

____________

Q - ?

Power:

P = I²·R

Current strength:

I = √ (P / R) = √ (12 / 270) ≈ 0.21 A

Charge:

Q = I·t = 0.21·2.5 = 0,525 C