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2x-y + 2z = 6 3x+2y-z = 4 4x + 3y - 3z = 1

2x-y + 2z = 6 3x+2y-z = 4 4x + 3y - 3z = 1
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2x-y + 2z = 6
3x+2y-z = 4
4x + 3y - 3z = 1

asked
User Izbassar Tolegen
by
8.2k points

1 Answer

5 votes

Answer:

Explanation:

2x-y + 2z = 6 3x+2y-z = 4 4x + 3y - 3z = 1-example-1
2x-y + 2z = 6 3x+2y-z = 4 4x + 3y - 3z = 1-example-2
answered
User SANJAY GUPTA
by
8.3k points
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