Question

.How many moles of NaOH are required to prepare 1.98 L of a 0.285 M NaOH solution?

Answer 1

Answer: 0.5643 mol NaOH

Step-by-step explanation:

First, I would start off with plugging in what you can for the molarity equation, which is:

M = mol/L

So, since you have 0.285M and 1.98 L you can plug that in where it fits. So it’d be:

0.285M = mol/1.98L

To isolate the mols on one side of the equation, you multiple both sides by 1.98 L. (Because it’s in the denominator. If you were trying to find L, you would divide by # of mols since it’s in the numerator).

After multiplying, your final answer should be 0.5643 mols of NaOH.