A student is provided with a specimen of tilapia of length 10cm. The student made a drawing of the specimen of length 12cm. Calculate the Magnification of the drawing.

Question

asked Aug 19, 2023 155k views

1 Answer

← Prev Question Next Question →

Ask a Question

Mohammad Rajabloo · Answer 1 · 2023-08-25T08:27:41+0000

Answer:

1.2 is the magnification of the drawing

Step-by-step explanation:

According to the question,

Actual length of tilapia specimen provided to a student = 10 cm

Drawing length made by student of the specimen= 12 cm

$\rm Magnification \: of \: the \: drawing= (Actual \: length \: of \: the \: specimen)/(Drawing \: length \: of \: the \: specimen) \\ \\ \rm= (12)/(10) \\ \\ \rm = 1.2$

A student is provided with a specimen of tilapia of length 10cm. The student made a drawing of the specimen of length 12cm. Calculate the Magnification of the drawing.

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories

Other Questions

A student is provided with a specimen of tilapia of length 10cm. The student made a drawing of the specimen of length 12cm. Calculate the Magnification of the drawing.​

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories

Other Questions

A student is provided with a specimen of tilapia of length 10cm. The student made a drawing of the specimen of length 12cm. Calculate the Magnification of the drawing.