Question

Two small plastic spheres having positive electrical charges are given. When they are 60.00cm apart, the repulsive force between them has the magnitude 0.250N.calculate the charge on each sphere

Answer 1

Charge 3.16 mkC microcoulomb

Step-by-step explanation:

Given:

q₁ = q₂ = q - Electrical charges

r = 60.00 sm = 0.60 m - Distance between charges

F = 0.250 N - Repulsive force between charges

___________________

q - ?

F = k·q₁·q₂ / r² = k·q·q / r² = k·q² / r²

Charge:

q = √ (F·r² / k )

q = r·√ (F / k )

q = 0.60· √ (0.250 / 9·10⁹) ≈ 3.16·10⁻⁶ C or:

q = 3.16 mkC (microcoulomb)

Answer 2

3.16 × 10‐⁶

Step-by-step explanation:

through coulomb's law

the force of attraction or repulsion of charges is given by the relation

F = k.q1.q2/r²

where your k = 9 × 10⁹