Question

What is the value of z where distance of between two point R(6, - 1, - 3) and S(3, 3, z) is 13?​

Answer 1

-15, 9

Explanation:

Substituting into the distance formula,

`√((6-3)^2+(-1-3)^2+(-3-z)^2)=13 \\ \\ √(25+(3+z)^2)=13 \\ \\ 25+(3+z)^2=169 \\ \\ (3+z)^2=144 \\ \\ 3+z=\pm 12 \\ \\ z=-3 \pm 12 \\ \\ z=-15, 9`