Question

Please help me with this math problem ​

Answer 1

`\sf (1)/(2)-(1)/(8)=\frac{\boxed{4}}{8}-(1)/(8)=\frac{\boxed{3}}{\boxed{8}}`

Explanation:

When adding or subtracting fractions that have different denominators, first rewrite the fractions as equivalent fractions with the same denominator. To do this, find the lowest common multiple (LCM) of the denominators.

The given subtraction is:

`\sf (1)/(2)-(1)/(8)`

The LCM of the denominators 2 and 8 is 8. Therefore, we need to rewrite the first fraction as an equivalent fraction with 8 as its denominator. To do this, multiply its numerator and denominator by 4:

`\implies \sf (1)/(2) *(4)/(4)=(4)/(8)`

Therefore:

`\implies \sf (1)/(2)-(1)/(8)=(4)/(8)-(1)/(8)`

To subtract fractions with the same denominator, simply subtract the numerators. (The denominator stays the same).

`\implies \sf (1)/(2)-(1)/(8)=(4)/(8)-(1)/(8)=(4-1)/(8)=(3)/(8)`

Final solution

`\sf (1)/(2)-(1)/(8)=\frac{\boxed{4}}{8}-(1)/(8)=\frac{\boxed{3}}{\boxed{8}}`