Question

The sum of four positive integers is 125. If you increase the first number by 4, decrease the second by 4, multiply the third by 4, and divide the fourth by 4, you produce four equal numbers. What is the smallest of the original numbers

Answer 1

Explanation:

a + b + c + d = 125

a + 4 = b - 4 = 4c = d/4

a + 8 = b

a = b - 8

16c = d

b = 4c + 4

4a + 16 = d

b - 8 + 4c + 4 + c + 16c = 125

4c + 4 - 8 + 4c + 4 + c + 16c = 125

25c = 125

c = 5

d = 16c = 80

4a + 16 = d = 80

4a = 64

a = 16

b = a + 8 = 16 + 8 = 24

so, the numbers are

16, 24, 5, 80