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Evaluate: 4y^0+x^1 if x=7 and y=8

Evaluate: 4y^0+x^1 if x=7 and y=8
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Evaluate: 4y^0+x^1 if x=7 and y=8

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User Phinz
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1 Answer

5 votes

Answer:

8

Explanation:

4y⁰ + x¹

Substitute y for 8 and x for 7

4(8)⁰ + 7¹

Since the value is raised to the power of 0,

= 1

1 + 7 = 8

answered
User Mavrosxristoforos
by
7.1k points
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