What are the solutions for the following system of equations?–x^2 + 3y = 203x^2 + 6y = 60 (–2, 8) and (2, 8) (–2, 8) and (0, 10) (2, 8) and (0, 10) (0, –10) and (0, 10)

Question

asked Apr 21, 2023 133k views

1 Answer

Julita · Answer 1 · 2023-04-25T09:59:28+0000

Solution:

Given the system of equations below

$\begin{gathered} -x^2+3y=20 \\ 3x^2+6y=60 \end{gathered}$

Using a graphing tool, the graphs of the system of equations is shown below

From the graph above,

The point of intersection of the two graphs is the solution to the system of equation.

Hence, the solution is

$(-2,8)\text{ and }(2,8)$