Question

suppose square a is a congruent to square be in the area of square C is 162 square feet what is the size length of square be if the three squares created a right triangle ?

Answer 1

`\begin{gathered} c^2=a^2+b^2 \\ c=\sqrt[]{162} \\ \text{If } \\ A\cong B \\ a=b \\ b^2+b^2=c^2 \\ 2b^2=162 \\ b^2=(162)/(2) \\ b^2=81 \\ b=\sqrt[]{81} \\ b=9 \end{gathered}`