Question

If ABCD is dilated by a factor of 12, thecoordinate of A' would be:65C4B21-6-5-4 43 -2 -1 0-1A2♡1to34 5A' = ([?], [])

Answer 1

Dilation with scale factor 1/2, then multiply by 1/2. (x, y) → (1/2x, 1/2y).

The coordinate of A is

`(-4,-2)`

Dilation with scale factor of 1/2

A'

`\begin{gathered} A^(\prime)=(1)/(2)(-4,-2) \\ A^(\prime)=(-2,1) \end{gathered}`

The final answer

`A^(\prime)=(-2,-1)`