Question

I'm having trouble learning about this could you answer the question and show the steps of how you got it

Answer 1

Step 1:

The area of the figure = Area of the trapezium + Area of a rectangle

Step 2:

The rectangle has dimensions of 7.8m by 6m

Find the area of rectangle A

`\begin{gathered} \text{Area of the rectangle = Length }*\text{ Breadth} \\ =\text{ 6 }*\text{ 7.8} \\ =46.8m^2 \end{gathered}`

Step 3:

Area of trapezium

`\begin{gathered} \text{Area of trapezium = }(1)/(2)(\text{ sum of the length of parallel sides ) }*\text{ height} \\ \text{Area of trapezium = }(1)/(2)(\text{ a+b ) }*\text{ height} \\ a\text{ = 10m , b = 12m , height = 5m} \end{gathered}`

Next

Find the area of the trapezium B

`\begin{gathered} \text{Area of trapezium = }(1)/(2)(\text{ a+b ) }*\text{ height} \\ \text{Area of trapezium = }(1)/(2)(\text{ 12+10) }*\text{ 5} \\ \text{Area of trapezium = }(1)/(2)(\text{22 ) }*\text{5} \\ \text{Area of trapezium = }(110)/(2) \\ \text{Area of trapezium = }55m^2 \end{gathered}`

Total area = 46.8 + 55

`\begin{gathered} \text{Total area = 46.8 + 55} \\ \text{Total area = 101.8 m}^2 \end{gathered}`

Final answer

`\begin{gathered} \text{Area of rectangle = 46.8 m}^2 \\ \text{Area of trapezium = 55 m}^2 \\ Totalarea=101.8m^2 \end{gathered}`