asked 156k views
4 votes
A gas at 1.25 atm is transfered to a 1L container with a final pressure of 3.75 atm. What was the initial volume of the container it was in, in L?

asked
User Mkuff
by
7.3k points

1 Answer

5 votes

Answer:


\text{The initial volume in the container was 3L}

Step-by-step explanation:

Here, we want to calculate the initial volume of the container

Mathematically, we know that volume and pressure are inversely related. What this means is that as volume increases, pressure is expected to decrease and as pressure increases, volume is expected to decrease

A mathematical link between these two is as follows:


P_1V_1=P_2V_2

The above is according to Boyles' law.

The values with subscript 1 are the initial values, while the values with the subscript 2 are the final values

Thus:

V1 = ?

P1 = 1.25 atm

V2 = 1L

P2 = 3.75 atm

From the relation:


V_1\text{ = }(P_2V_2)/(P_1)\text{ = }(3.75*1)/(1.25)\text{ = 3 L}

answered
User YaDav MaNish
by
8.2k points
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