Question

Not to sure if I got the correct numerator or denominator.

Answer 1

Simplify the rational expression bellow:

`\begin{gathered} (12n^(2)-29n-8)/(28n^(2)-5n-3)= \\ \frac{(4n+1)(3n-8)_{}}{(4n+1)(7n-3)}= \\ (3n-8)/(7n-3) \end{gathered}`