Question

My subject is Statistics and the homeworks topic is Hypothesis Testing (z-tests). I really need help on this question since I don't understand and it is due tomorrow. Please help!

Answer 1

Step-by-step explanation:

We start by declaring the null hypothesis

The null hypothesis here is that OHS averages 65 tardines per day

Now, let us get the alternative

We start by getting the p-value, which is an extension of the z value

The z value can be calculated as:

`\begin{gathered} z\text{ = }(x-\mu)/(\sigma) \\ \\ z\text{ = }(65-59)/(4.5)\text{ = 1.333} \end{gathered}`

Now, we get the value:

`p\text{ = (z < 1.333)}`

For a two-tailed test, we have that:

`p\text{ = 0}.183518`

Now, let us get our conclusion

From the value of p, we can see that the result is not significant

Since p is greater than the level of significance, we accept the null hypothesis (The principal's claims) and say there is no convincing evidence that the average number of tardines is different from the principal's claims