Question

The distance h a body will move in a free fall is expressed by the formula h=1/2 gt2 if g =980 cm per sec2 and t= 20 sec, the distance h is

Answer 1

Given the distance h as

`h=(1)/(2)t^2`

Here,

`\begin{gathered} g=980\text{ cm/sec}^2 \\ \\ t=20\text{ sec} \end{gathered}`

Therefore, the distance h is: 196000 cm

`h=(1)/(2)*980*20^2=196000\text{ cm}`