Question

A rectangle has perimeter 92 cm and its length is 1 cm more than twice its width.

Answer 1

Length = L

Width = W

Perimeter = P

`L\text{ = 2W + 1}`

`P\text{ = 2 (L + W)}`
`\begin{gathered} P\text{ = 2L + 2W = 92} \\ 2(2W\text{ + 1) + 2W = 92} \\ 4W\text{ + 2 + 2W = 92} \\ 6W+2=92^{} \\ 6W\text{ = 92 - 2} \\ 6W\text{ = 90} \\ W\text{ = }(90)/(6) \\ W\text{ = 15 cm} \end{gathered}`
`\begin{gathered} L\text{ = 2W + 1} \\ L\text{ = 2(15) + 1} \\ L\text{ = 30 + 1} \\ L\text{ = 31 cm} \end{gathered}`

CONCLUSION:

The length of the rectangle is 31 cm and The width is 15 cm.