Question 1: 
Adding 2 to both sides of the equation gives 

Now, the absolute value decomposes the above equation into two separate equations 

The first equation gives 

The second equation gives 

The graph of the system is 
We see that the solutions exists at x =-1. 
Question 2. 
Adding 2 to both sides of the equation gives 

Decomposing the absolute value on LHS gives us two equations 

Solving the first equation gives

Solving the second equation gives

Hence, the solution to the equation is 

The graph of the solutions is 
We see that the solution is at x = -1 and x = 1; hence, our solution is confirmed.