Question

The translation < -2,5 > maps J onto J'. If the coordinates of J are (7, -3),what are the coordinates of J'?

Answer 1

The coordinates of J' is;

`J^(\prime)(5,2)`

Step-by-step explanation:

Given the coordinate of J;

`J(7,-3)`

And the translation;

`<-2,5>`

that maps J onto J'.

So, the coordinates of J' will be;

`\begin{gathered} J(x,y)\rightarrow J^(\prime)(x-2,y+5) \\ J(7,-3)\rightarrow J^(\prime)(7-2,-3+5) \\ J(7,-3)\rightarrow J^(\prime)(5,2) \end{gathered}`

Therefore, the coordinates of J' is;

`J^(\prime)(5,2)`