The question is to divided ;
6y^2 -11 y +15 by 2y + 7
Performing long division, starting by 6y^2 and 2y to get ;
3y
Perform product -----[3y {2y+7}] ------6y^2 +21 ---------a)
Cancel the 6y^2 terms by subtaction.This means subtact 6y^2 +21 from 6y^2-11y +7
This will give : -32y +7 -----------b)
Then proceed with division : Divide - 32y + 7 by 2y +7
This will give: