Question

Simplify the expression.(-5r^2s^7)^3÷r

Answer 1

Use the laws of exponents to simplify the expression:

`\frac{(-5r^2s^7)^3^{}}{r}`

We know that:

`\begin{gathered} (ab)^n=a^nb^n \\ (a^n)^m=a^(n* m) \\ (a^n)/(a^m)=a^(n-m) \end{gathered}`

Then:

`\begin{gathered} ((-5r^2s^7)^3)/(r)=((-5)^3(r^2)^3(s^7)^3)/(r) \\ =(-125r^6s^(21))/(r) \\ =-125r^(6-1)s^(21) \\ =-125r^5s^(21) \end{gathered}`

Therefore:

`((-5r^2s^7)^3)/(r)=-125r^5s^(21)`