asked 216k views
2 votes
A sample of oxygen gas at 285 K exerts 3.21 atm of pressure on its 47.6 L container. How many moles of O2 are in the sample? The ideal gas constant is 0.0821 L*atm/mol*K. Round your answer to the nearest 0.01 and include correct units.

asked
User Matroska
by
8.6k points

1 Answer

1 vote

answer and explanation

we are asked to determine the number of mols of Oxygen in the sample and we can do this using the ideal gas equation

PV = nRT

and when we rearrange the equation to make n subject of the formula, we gent :

n = PV/RT

= (3.21atm x 47.6L) / (0.0821 x 285K)

= 152.796 / 23.3985

= 6.53 mols

answered
User Mikeesouth
by
7.0k points
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