Question

At the tri-county track meet Jada won the 100 meter race in 12 9/10 seconds. The runner up finished in 13 1/10 seconds how many seconds faster was Jada then the funner up?

Answer 1

We have

`\begin{gathered} 12\text{ }(9)/(10)\text{ = 12+}(9)/(10)\text{ = }(120)/(10)+(9)/(10)=(129)/(10) \\ 13\text{ }(1)/(10)=13+(1)/(10)=(130)/(10)+(1)/(10)=(131)/(10) \end{gathered}`

Then, the diference is

`(131)/(10)-(129)/(10)=(2)/(10)=(1)/(5)`

So, Jada was 1/5 seconds faster than the second place.