Question

I need some help please do this

Answer 1

let us the substitution x=y^2. So we get

`\begin{gathered} y^2-3y-28=0 \\ (y-7)(y+4)=0\rightarrow \\ y=7,y=-4 \end{gathered}`

having this we get that the answer are:

`x=49`

The option y=-4, can not be used because we get that

`\sqrt[]{x}=-4`

and it is not possible