Question

Express the confidence interval (30.2% ,44%) in the form of ˆp ± ME.

Answer 1

First, express the interval in decimal form:

(0.302, 0.44)

Now find the average value of the endpoints of the interval. This will give us the value of p:

`p=(0.302+0.44)/(2)=0.371`

Now find the semi difference of the endpoints to have the value of ME:

`ME=(0.44-0.302)/(2)=0.069`

Now express the interval in the required form:

`(0.32,0.44)=0.371\pm0.069`