Question

Find h(-8)=2(t+5)^2+4

Answer 1

Given the equation :

`h(t)=2(t+5)^2+4`

We need to find the value of h(-8)

So, substitute with t = -8 at the given equation :

`\begin{gathered} h(-8)=2(-8+5)^2+4 \\ h(-8)=2(-3)^2+4 \\ h(-8)=2\cdot9+4 \\ h(-8)=18+4 \\ \\ h(-8)=22 \end{gathered}`

So, the answer is : the value of h(-8) = 22