Question

Write the number in standard complex number form, a + bi.

Answer 1

To solve the exercise, we distribute the denominator of the fraction, and then we simplify:

`\begin{gathered} (2-6i)/(3)=(2)/(3)-(6i)/(3) \\ \text{ Simplify} \\ (2-6i)/(3)=(2)/(3)-(2\cdot3i)/(3) \\ (2-6i)/(3)=(2)/(3)-2i \end{gathered}`

Therefore, the given complex number in its standard form is:

`$$\boldsymbol{(2)/(3)-2i}$$`