Question

BD bisects ZABC such that mZABD =(4x – 5) and mZDBC =(3x + 2)Find the value of ..17

Answer 1

For this case we know that

m m < DBC = 3x+2

So then we can do the following:

4x -5 = 3x+2

4x-3x = 5+2= 7

x = 7