Question

Need help with this exercise. It’s from a review the real test is next week need more explanation so I already know what to do on the test.

Answer 1

Options 1 and 4

Step-by-step explanation

First, let us find the length of the third side of the right triangle. To do this apply the Pythagoras theorem.

Let the length of the third side of the triangle be x.

It implies that:

`\begin{gathered} x^2+8^2=17^2 \\ x^2=17^2-8^2 \\ x^2=289-64=225 \\ x=\sqrt[]{225} \\ x=15 \end{gathered}`

Now, we can find the value of sinA, tanA, and sinC.

According to trigonometric ratios, SOHCAHTOA, we have that:

`\begin{gathered} \sin A=\frac{\text{opposite}}{\text{hypotenuse}} \\ \tan A=\frac{\text{opposite}}{\text{adjacent}} \\ \sin C=\frac{\text{opposite}}{\text{hypotenuse}} \end{gathered}`

Therefore:

`\begin{gathered} \sin A=(15)/(17) \\ \tan A=(15)/(8) \\ \sin C=(8)/(17) \end{gathered}`

Hence, the correct options are options 1 and 4.